RecipeTransformer

Template documentation (for the template shown above, sometimes hidden or invisible)

Usage Edit

You would use this template to transform a template from Template:RecipeInfoBox to one of the following template based on the style tag:

• style=recipetable: Template:RecipeTableRow
• style=iconmini: Template:IconMini
• style=value: Template:Value
• style=iconmed: Template:IconMed

To use it, simply use it as you would for any of the subtemplates. Then, include

|style={{{style|}}}

into the template. This will tell the template to transform it into its derivative class.

Variables Edit

Example Edit

For example - this is the code for the page Potent Lyrium Potion Recipe

{{RecipeTransformer
|style={{{style|}}}
|name=[[Potent Lyrium Potion Recipe]]
|description=This is a recipe designed by the Chantry for distilling raw lyrium into a refined potion, one that can be used to augment reserves of mana.
|type=[[Recipes|Recipe]]
|value=74500
|icon=rcp_ico_herbalism_4.png
|ingredient1=[[Lyrium Dust]]
|quantity1=4
|ingredient_icon1=rgt_ico_lyriumdust.png
|ingredient2=[[Flask]]
|quantity2=1
|ingredient_icon2=rgt_ico_flask.png
|ingredient3=[[Distillation Agent]]
|quantity3=2
|ingredient_icon3=rgt_ico_distill_agnt.png
|ingredient4=[[Concentrator Agent]]
|quantity4=2
|ingredient_icon4=rgt_ico_conc_agnt.png
|result=[[Potent Lyrium Potion]]
|result_icon=ico_lyrium_potion.png
|requires=[[Herbalism: Rank 4]]
|appearances=''[[Dragon Age: Origins]]''
}}

When Potent Lyrium Potion Recipe is displayed on its own page or included without parameters, it shows up as

{{:Potent Lyrium Potion Recipe}}

Transformation Edit

However, if it is included as follows,

{{RecipeTableHeader|
{{:Potent Lyrium Potion Recipe|style=recipetable}}
}}

it shows up as

Recipe	Makes	Ingredients	Required skill
Potent Lyrium Potion Recipe	Potent Lyrium Potion	4 1 2 2	Herbalism: Rank 4

Documentation transcluded from Template:RecipeTransformer/doc.